Optimal. Leaf size=166 \[ -\frac{3 e \left (d^2-e^2 x^2\right )^{p-1} \, _2F_1\left (1,p-1;p;1-\frac{e^2 x^2}{d^2}\right )}{2 d^2 (1-p)}+\frac{2 e^2 (4-p) x \left (1-\frac{e^2 x^2}{d^2}\right )^{-p} \left (d^2-e^2 x^2\right )^p \, _2F_1\left (\frac{1}{2},3-p;\frac{3}{2};\frac{e^2 x^2}{d^2}\right )}{d^5}-\frac{2 e \left (d^2-e^2 x^2\right )^{p-2}}{2-p}-\frac{d \left (d^2-e^2 x^2\right )^{p-2}}{x} \]
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Rubi [A] time = 0.225759, antiderivative size = 166, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 9, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.36, Rules used = {852, 1807, 1652, 446, 79, 65, 12, 246, 245} \[ -\frac{3 e \left (d^2-e^2 x^2\right )^{p-1} \, _2F_1\left (1,p-1;p;1-\frac{e^2 x^2}{d^2}\right )}{2 d^2 (1-p)}+\frac{2 e^2 (4-p) x \left (1-\frac{e^2 x^2}{d^2}\right )^{-p} \left (d^2-e^2 x^2\right )^p \, _2F_1\left (\frac{1}{2},3-p;\frac{3}{2};\frac{e^2 x^2}{d^2}\right )}{d^5}-\frac{2 e \left (d^2-e^2 x^2\right )^{p-2}}{2-p}-\frac{d \left (d^2-e^2 x^2\right )^{p-2}}{x} \]
Antiderivative was successfully verified.
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Rule 852
Rule 1807
Rule 1652
Rule 446
Rule 79
Rule 65
Rule 12
Rule 246
Rule 245
Rubi steps
\begin{align*} \int \frac{\left (d^2-e^2 x^2\right )^p}{x^2 (d+e x)^3} \, dx &=\int \frac{(d-e x)^3 \left (d^2-e^2 x^2\right )^{-3+p}}{x^2} \, dx\\ &=-\frac{d \left (d^2-e^2 x^2\right )^{-2+p}}{x}-\frac{\int \frac{\left (d^2-e^2 x^2\right )^{-3+p} \left (3 d^4 e-2 d^3 e^2 (4-p) x+d^2 e^3 x^2\right )}{x} \, dx}{d^2}\\ &=-\frac{d \left (d^2-e^2 x^2\right )^{-2+p}}{x}-\frac{\int -2 d^3 e^2 (4-p) \left (d^2-e^2 x^2\right )^{-3+p} \, dx}{d^2}-\frac{\int \frac{\left (d^2-e^2 x^2\right )^{-3+p} \left (3 d^4 e+d^2 e^3 x^2\right )}{x} \, dx}{d^2}\\ &=-\frac{d \left (d^2-e^2 x^2\right )^{-2+p}}{x}-\frac{\operatorname{Subst}\left (\int \frac{\left (d^2-e^2 x\right )^{-3+p} \left (3 d^4 e+d^2 e^3 x\right )}{x} \, dx,x,x^2\right )}{2 d^2}+\left (2 d e^2 (4-p)\right ) \int \left (d^2-e^2 x^2\right )^{-3+p} \, dx\\ &=-\frac{2 e \left (d^2-e^2 x^2\right )^{-2+p}}{2-p}-\frac{d \left (d^2-e^2 x^2\right )^{-2+p}}{x}-\frac{1}{2} (3 e) \operatorname{Subst}\left (\int \frac{\left (d^2-e^2 x\right )^{-2+p}}{x} \, dx,x,x^2\right )+\frac{\left (2 e^2 (4-p) \left (d^2-e^2 x^2\right )^p \left (1-\frac{e^2 x^2}{d^2}\right )^{-p}\right ) \int \left (1-\frac{e^2 x^2}{d^2}\right )^{-3+p} \, dx}{d^5}\\ &=-\frac{2 e \left (d^2-e^2 x^2\right )^{-2+p}}{2-p}-\frac{d \left (d^2-e^2 x^2\right )^{-2+p}}{x}+\frac{2 e^2 (4-p) x \left (d^2-e^2 x^2\right )^p \left (1-\frac{e^2 x^2}{d^2}\right )^{-p} \, _2F_1\left (\frac{1}{2},3-p;\frac{3}{2};\frac{e^2 x^2}{d^2}\right )}{d^5}-\frac{3 e \left (d^2-e^2 x^2\right )^{-1+p} \, _2F_1\left (1,-1+p;p;1-\frac{e^2 x^2}{d^2}\right )}{2 d^2 (1-p)}\\ \end{align*}
Mathematica [C] time = 0.135839, size = 83, normalized size = 0.5 \[ \frac{\left (1-\frac{d^2}{e^2 x^2}\right )^{-p} (d-e x)^p (d+e x)^p F_1\left (4-2 p;-p,3-p;5-2 p;\frac{d}{e x},-\frac{d}{e x}\right )}{2 e^3 (p-2) x^4} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.661, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{p}}{{x}^{2} \left ( ex+d \right ) ^{3}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (-e^{2} x^{2} + d^{2}\right )}^{p}}{{\left (e x + d\right )}^{3} x^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (-e^{2} x^{2} + d^{2}\right )}^{p}}{e^{3} x^{5} + 3 \, d e^{2} x^{4} + 3 \, d^{2} e x^{3} + d^{3} x^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (- \left (- d + e x\right ) \left (d + e x\right )\right )^{p}}{x^{2} \left (d + e x\right )^{3}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (-e^{2} x^{2} + d^{2}\right )}^{p}}{{\left (e x + d\right )}^{3} x^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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